3.2.62 \(\int \frac {1}{(a+b \cosh ^{-1}(c x))^{7/2}} \, dx\) [162]

Optimal. Leaf size=188 \[ -\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {4 e^{a/b} \sqrt {\pi } \text {Erf}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c}+\frac {4 e^{-\frac {a}{b}} \sqrt {\pi } \text {Erfi}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c} \]

[Out]

-4/15*x/b^2/(a+b*arccosh(c*x))^(3/2)+4/15*exp(a/b)*erf((a+b*arccosh(c*x))^(1/2)/b^(1/2))*Pi^(1/2)/b^(7/2)/c+4/
15*erfi((a+b*arccosh(c*x))^(1/2)/b^(1/2))*Pi^(1/2)/b^(7/2)/c/exp(a/b)-2/5*(c*x-1)^(1/2)*(c*x+1)^(1/2)/b/c/(a+b
*arccosh(c*x))^(5/2)-8/15*(c*x-1)^(1/2)*(c*x+1)^(1/2)/b^3/c/(a+b*arccosh(c*x))^(1/2)

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Rubi [A]
time = 0.48, antiderivative size = 188, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {5880, 5951, 5953, 3388, 2211, 2236, 2235} \begin {gather*} \frac {4 \sqrt {\pi } e^{a/b} \text {Erf}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c}+\frac {4 \sqrt {\pi } e^{-\frac {a}{b}} \text {Erfi}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c}-\frac {8 \sqrt {c x-1} \sqrt {c x+1}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {2 \sqrt {c x-1} \sqrt {c x+1}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*ArcCosh[c*x])^(-7/2),x]

[Out]

(-2*Sqrt[-1 + c*x]*Sqrt[1 + c*x])/(5*b*c*(a + b*ArcCosh[c*x])^(5/2)) - (4*x)/(15*b^2*(a + b*ArcCosh[c*x])^(3/2
)) - (8*Sqrt[-1 + c*x]*Sqrt[1 + c*x])/(15*b^3*c*Sqrt[a + b*ArcCosh[c*x]]) + (4*E^(a/b)*Sqrt[Pi]*Erf[Sqrt[a + b
*ArcCosh[c*x]]/Sqrt[b]])/(15*b^(7/2)*c) + (4*Sqrt[Pi]*Erfi[Sqrt[a + b*ArcCosh[c*x]]/Sqrt[b]])/(15*b^(7/2)*c*E^
(a/b))

Rule 2211

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[F^(g*(e - c*(
f/d)) + f*g*(x^2/d)), x], x, Sqrt[c + d*x]], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !TrueQ[$UseGamma]

Rule 2235

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2
]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2236

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erf[(c + d*x)*Rt[(-b)*Log[F],
 2]]/(2*d*Rt[(-b)*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 3388

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rule 5880

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[Sqrt[1 + c*x]*Sqrt[-1 + c*x]*((a + b*ArcCosh[c
*x])^(n + 1)/(b*c*(n + 1))), x] - Dist[c/(b*(n + 1)), Int[x*((a + b*ArcCosh[c*x])^(n + 1)/(Sqrt[1 + c*x]*Sqrt[
-1 + c*x])), x], x] /; FreeQ[{a, b, c}, x] && LtQ[n, -1]

Rule 5951

Int[(((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_)*((f_.)*(x_))^(m_.))/(Sqrt[(d1_) + (e1_.)*(x_)]*Sqrt[(d2_) + (e2_
.)*(x_)]), x_Symbol] :> Simp[(f*x)^m*((a + b*ArcCosh[c*x])^(n + 1)/(b*c*(n + 1)))*Simp[Sqrt[1 + c*x]/Sqrt[d1 +
 e1*x]]*Simp[Sqrt[-1 + c*x]/Sqrt[d2 + e2*x]], x] - Dist[f*(m/(b*c*(n + 1)))*Simp[Sqrt[1 + c*x]/Sqrt[d1 + e1*x]
]*Simp[Sqrt[-1 + c*x]/Sqrt[d2 + e2*x]], Int[(f*x)^(m - 1)*(a + b*ArcCosh[c*x])^(n + 1), x], x] /; FreeQ[{a, b,
 c, d1, e1, d2, e2, f, m}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] && LtQ[n, -1]

Rule 5953

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d1_) + (e1_.)*(x_))^(p_.)*((d2_) + (e2_.)*(x_))^(p_
.), x_Symbol] :> Dist[(1/(b*c^(m + 1)))*Simp[(d1 + e1*x)^p/(1 + c*x)^p]*Simp[(d2 + e2*x)^p/(-1 + c*x)^p], Subs
t[Int[x^n*Cosh[-a/b + x/b]^m*Sinh[-a/b + x/b]^(2*p + 1), x], x, a + b*ArcCosh[c*x]], x] /; FreeQ[{a, b, c, d1,
 e1, d2, e2, n}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] && IGtQ[p + 3/2, 0] && IGtQ[m, 0]

Rubi steps

\begin {align*} \int \frac {1}{\left (a+b \cosh ^{-1}(c x)\right )^{7/2}} \, dx &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}+\frac {(2 c) \int \frac {x}{\sqrt {-1+c x} \sqrt {1+c x} \left (a+b \cosh ^{-1}(c x)\right )^{5/2}} \, dx}{5 b}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}+\frac {4 \int \frac {1}{\left (a+b \cosh ^{-1}(c x)\right )^{3/2}} \, dx}{15 b^2}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {(8 c) \int \frac {x}{\sqrt {-1+c x} \sqrt {1+c x} \sqrt {a+b \cosh ^{-1}(c x)}} \, dx}{15 b^3}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {8 \text {Subst}\left (\int \frac {\cosh (x)}{\sqrt {a+b x}} \, dx,x,\cosh ^{-1}(c x)\right )}{15 b^3 c}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {4 \text {Subst}\left (\int \frac {e^{-x}}{\sqrt {a+b x}} \, dx,x,\cosh ^{-1}(c x)\right )}{15 b^3 c}+\frac {4 \text {Subst}\left (\int \frac {e^x}{\sqrt {a+b x}} \, dx,x,\cosh ^{-1}(c x)\right )}{15 b^3 c}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {8 \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \cosh ^{-1}(c x)}\right )}{15 b^4 c}+\frac {8 \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \cosh ^{-1}(c x)}\right )}{15 b^4 c}\\ &=-\frac {2 \sqrt {-1+c x} \sqrt {1+c x}}{5 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}}-\frac {4 x}{15 b^2 \left (a+b \cosh ^{-1}(c x)\right )^{3/2}}-\frac {8 \sqrt {-1+c x} \sqrt {1+c x}}{15 b^3 c \sqrt {a+b \cosh ^{-1}(c x)}}+\frac {4 e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c}+\frac {4 e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \cosh ^{-1}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c}\\ \end {align*}

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Mathematica [A]
time = 0.49, size = 214, normalized size = 1.14 \begin {gather*} \frac {-6 \sqrt {\frac {-1+c x}{1+c x}} (1+c x)-\frac {2 e^{-\cosh ^{-1}(c x)} \left (a+b \cosh ^{-1}(c x)\right ) \left (-2 a+b-2 b \cosh ^{-1}(c x)+2 e^{\frac {a}{b}+\cosh ^{-1}(c x)} \sqrt {\frac {a}{b}+\cosh ^{-1}(c x)} \left (a+b \cosh ^{-1}(c x)\right ) \Gamma \left (\frac {1}{2},\frac {a}{b}+\cosh ^{-1}(c x)\right )\right )}{b^2}-\frac {2 e^{-\frac {a}{b}} \left (a+b \cosh ^{-1}(c x)\right ) \left (e^{\frac {a}{b}+\cosh ^{-1}(c x)} \left (2 a+b+2 b \cosh ^{-1}(c x)\right )+2 b \left (-\frac {a+b \cosh ^{-1}(c x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {a+b \cosh ^{-1}(c x)}{b}\right )\right )}{b^2}}{15 b c \left (a+b \cosh ^{-1}(c x)\right )^{5/2}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[(a + b*ArcCosh[c*x])^(-7/2),x]

[Out]

(-6*Sqrt[(-1 + c*x)/(1 + c*x)]*(1 + c*x) - (2*(a + b*ArcCosh[c*x])*(-2*a + b - 2*b*ArcCosh[c*x] + 2*E^(a/b + A
rcCosh[c*x])*Sqrt[a/b + ArcCosh[c*x]]*(a + b*ArcCosh[c*x])*Gamma[1/2, a/b + ArcCosh[c*x]]))/(b^2*E^ArcCosh[c*x
]) - (2*(a + b*ArcCosh[c*x])*(E^(a/b + ArcCosh[c*x])*(2*a + b + 2*b*ArcCosh[c*x]) + 2*b*(-((a + b*ArcCosh[c*x]
)/b))^(3/2)*Gamma[1/2, -((a + b*ArcCosh[c*x])/b)]))/(b^2*E^(a/b)))/(15*b*c*(a + b*ArcCosh[c*x])^(5/2))

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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (a +b \,\mathrm {arccosh}\left (c x \right )\right )^{\frac {7}{2}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a+b*arccosh(c*x))^(7/2),x)

[Out]

int(1/(a+b*arccosh(c*x))^(7/2),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*arccosh(c*x))^(7/2),x, algorithm="maxima")

[Out]

integrate((b*arccosh(c*x) + a)^(-7/2), x)

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*arccosh(c*x))^(7/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (a + b \operatorname {acosh}{\left (c x \right )}\right )^{\frac {7}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*acosh(c*x))**(7/2),x)

[Out]

Integral((a + b*acosh(c*x))**(-7/2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*arccosh(c*x))^(7/2),x, algorithm="giac")

[Out]

integrate((b*arccosh(c*x) + a)^(-7/2), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )}^{7/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a + b*acosh(c*x))^(7/2),x)

[Out]

int(1/(a + b*acosh(c*x))^(7/2), x)

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